mirror of
https://github.com/amyinspace/MagicSetEditor2.git
synced 2026-06-10 04:57:00 -04:00
436c437189
add compiler directives
89 lines
2.5 KiB
C++
89 lines
2.5 KiB
C++
//+----------------------------------------------------------------------------+
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//| Description: Magic Set Editor - Program to make card games |
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//| Copyright: (C) Twan van Laarhoven and the other MSE developers |
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//| License: GNU General Public License 2 or later (see file COPYING) |
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//+----------------------------------------------------------------------------+
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// ----------------------------------------------------------------------------- : Includes
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#include <util/prec.hpp>
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#include <gfx/polynomial.hpp>
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#include <complex>
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// ----------------------------------------------------------------------------- : Solving
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UInt solve_linear(double a, double b, double* root) {
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if (a == 0) {
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if (b == 0) {
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root[0] = 0;
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return 1;
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} else {
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return 0;
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}
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} else {
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root[0] = -b / a;
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return 1;
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}
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}
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UInt solve_quadratic(double a, double b, double c, double* roots) {
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if (a == 0) {
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return solve_linear(b, c, roots);
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} else {
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double d = b*b - 4*a*c;
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if (d < 0) return 0;
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roots[0] = (-b - sqrt(d)) / (2*a);
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roots[1] = (-b + sqrt(d)) / (2*a);
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return 2;
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}
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}
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UInt solve_cubic(double a, double b, double c, double d, double* roots) {
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if (a == 0) {
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return solve_quadratic(b, c, d, roots);
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} else {
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return solve_cubic(b/a, c/a, d/a, roots);
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}
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}
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// cubic root
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template <typename T>
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inline T curt(T x) { return pow(x, 1.0 / 3); }
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UInt solve_cubic(double a, double b, double c, double* roots) {
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double p = b - a*a / 3;
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double q = c + (2 * a*a*a - 9 * a * b) / 27;
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if (p == 0 && q == 0) {
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roots[0] = -a / 3;
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return 1;
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}
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complex<double> u;
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if (q > 0) {
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u = curt(q/2 + sqrt(complex<double>(q*q / 4 + p*p*p / 27)));
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} else {
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u = curt(q/2 - sqrt(complex<double>(q*q / 4 + p*p*p / 27)));
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}
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// now for the complex part
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// rot1(1, 0)
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complex<double> rot2(-0.5, sqrt(3.0) / 2);
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complex<double> rot3(-0.5, -sqrt(3.0) / 2);
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complex<double> x1 = p / (3.0 * u) - u - a / 3.0;
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complex<double> x2 = p / (3.0 * u * rot2) - u * rot2 - a / 3.0;
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complex<double> x3 = p / (3.0 * u * rot3) - u * rot3 - a / 3.0;
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// check if the solutions are real
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UInt count = 0;
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if (abs(x1.imag()) < 0.00001) {
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roots[count] = x1.real();
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count += 1;
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}
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if (abs(x2.imag()) < 0.00001) {
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roots[count] = x2.real();
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count += 1;
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}
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if (abs(x3.imag()) < 0.00001) {
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roots[count] = x3.real();
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count += 1;
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}
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return count;
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}
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